Question:
So I have a group of files with the following file names:
52 39 118 070 13200 5480.txt
83 39 010 392 01000 9970.txt
37 39 880 163 17802 0473.txt
I am trying to rename them to something like:
2012 File Description (52-39-118-070-13200-5480).txt
2012 File Description (83-39-010-392-01000-9970).txt
2012 File Description (37-39-880-163-17802-0473).txt
But, I can’t figure out what the corresponding regular expression would be, and how to code it into PowerShell. I see tons of examples to remove spaces or underscores, but nothing to add to a string.
Please note that “2012 File Description” would be constant for all files being renamed. The only thing that I would like to change is have the original file name moved into the parentheses and change the spaces to dashes.
Thank you.
Answer:
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"52 39 118 070 13200 5480.txt" -replace "(.*)(\.txt)",'2012 File Description ($1)$2' |
gives:
2012 File Description (52 39 118 070 13200 5480).txt
Important: the replacement string is using single quotes, because the dollar sign “$” character needs to be escaped if it appears in a string that is quoted with double quotes.
Alternatively I could have written:
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"52 39 118 070 13200 5480.txt" -replace "(.*)(\.txt)","2012 File Description (`$1)`$2" |